# lastIndexWhere method

1. @override

int lastIndexWhere(

1. bool test(
   1. E element
   ), [
2. int? start

])
override

The last index in the list that satisfies the provided `test`.

Searches the list from index `start` to 0. The first time an object `o` is encountered so that `test(o)` is true, the index of `o` is returned. If `start` is omitted, it defaults to the length of the list.

    final notes = <String>['do', 're', 'mi', 're'];
    final first = notes.lastIndexWhere((note) => note.startsWith('r')); // 3
    final second = notes.lastIndexWhere((note) => note.startsWith('r'),
        2); // 1

Returns -1 if `element` is not found.

    final notes = <String>['do', 're', 'mi', 're'];
    final index = notes.lastIndexWhere((note) => note.startsWith('k'));
    print(index); // -1

## Implementation

    @override
    int lastIndexWhere(bool Function(E element) test, [int? start]) {
      if (isEmpty) return -1;
      start ??= _length - 1;
      if (start < 0 || start >= _length) {
        return -1;
      }

      _Node<E>? current = _getNodeAt(start);
      for (int i = start; i >= 0; i--) {
        if (test(current!.value)) {
          return i;
        }
        current = current.prev;
      }
      return -1;
    }